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Old December 31, 2000, 04:14 PM   #13
Destructo6
Senior Member
 
Join Date: March 18, 1999
Location: Nogales, AZ USA
Posts: 4,001
Ah, I think I have it now...

We're measuring the small angle from of an isosceles triangle, whose legs are at the edge of the group, not a right triangle whose long leg is perpendicular to the target and centered in the group, having the hypotenuse at the edge of the group. That would explain why my calculation was exactly double the value given by the proper definition of MOA.

That's interesting.



[Edited by Destructo6 on 12-31-2000 at 11:08 PM]
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